73=-16t^2+73

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Solution for 73=-16t^2+73 equation: 



73=-16t^2+73

We move all terms to the left:

73-(-16t^2+73)=0

We get rid of parentheses

16t^2-73+73=0

We add all the numbers together, and all the variables

16t^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{32}=0$

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